Assuming that the reaction from A and C to AC5 is only
one-step (or an elementary reaction) with a balanced chemical reaction of:
<span>A + 5 C ---> AC5 </span>
Therefore the formation constant can be easily calculated
using the following formula for formation constant:
Kf = product of products concentrations / product of reactants
concentration
<span>Kf = [AC5] / [A] [C]^5 </span>
---> Any coefficient from the balanced chemical
reaction becomes a power in the formula
Substituting the given values into the equation:
Kf = 0.100 M / (0.100 M) (0.0110 M)^5
Kf = 6,209,213,231
or in simpler terms
<span>Kf = 6.21 * 10^9 (ANSWER)</span>
Equation for Half life :
A = a(0.5)^(t/h)
A is current amount, "a" is initial amount, h is halflife, t is time
5 = 40(0.5)^(t/1.3x10^9)
5/40 = (0.5)^(t/1.3x10^9)
take the log of both sides , power rule
Log(5/40) = (t/1.3x10^9) * Log(0.5)
(1.3x10^9) * Log(5/40) / Log(0.5) = t
3.9x10^9 years = t
And if you think about what a half life is, the time it take for the amount to reduce to half.
40/2 = 20
20/2 = 10
10/2 = 5
It went through 3 half-lifes
3 * 1.3x10^9 = 3.9x10^9 years
Answer:
i think it's 3 because there aren't any indexes so that leaves us with one atom of Ca, one atom of O, and one atom of H