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2 years ago

Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.

Mathematics

1 answer:

Kipish [7]2 years ago

8 0

Hello!!

Equation forms:

$y = \frac{x^2}{4} + \frac{x}{2} + \frac{13}{4}$

Therefore, $x^2 - 2x + 4y - 13 = 0$

And, this is how your graph would look

Good luck :)

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this is how i did it
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2 years ago

Find the measures of the following angles.

makvit [3.9K]

Answer:

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Step-by-step explanation:

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2 years ago

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6) Find the measure of ∠G.

topjm [15]

Answer:

m<G = 71

Step-by-step explanation:

Find x first

7x + 1 + 6x - 6 + 55 = 180

Combine like terms:

13x + 50 = 180

- 50 - 50

13x = 130

/13 /13

x = 10

Then apply to problem

7 (10) + 1

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1 year ago

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Pls help this is pretty urgent

KIM [24]

Answer:

(a) 0

(b) f(x) = g(x)

Step-by-step explanation:

Given rational function:

$f(x)=\dfrac{x^2+2x+1}{x^2-1}$

Part (a)

Factor the numerator and denominator of the given rational function:

$\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}$

Substitute x = -1 to find the limit:

$\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0$

Therefore:

$\displaystyle \lim_{x \to -1}f(x)=0$

Part (b)

From part (a), we can see that the simplified function f(x) is the same as the given function g(x). Therefore, f(x) = g(x).

Part (c)

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero). Therefore, the quotient approaches infinity.

$\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty$

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9 months ago

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