Synthesis reactions are reactions that occur when two different atoms or molecules interact to form a different molecule or compound. Most of the time, when a synthesis reaction occurs, energy is released and the reaction is exothermic
Answer:
412.1kJ
Explanation:
For the reaction , from the question -
4Fe (s) + 3O₂ (g) → 2Fe₂O₃ (s)
Δ Hrxn = Δ H°f (products) - Δ H°f (reactants)
In case the compound is in its standard state , enthalphy of formation is zero
Hence ,
for the above reaction ,
ΔHrxn =( 2 * Δ H° (Fe₂O₃ )) - [ ( 4 *Δ H° Fe ) + (3 * Δ H° O₂ )]
The value for Δ H°(Fe₂O₃ ) = - 824.2kJ/mol
Δ H° Fe = 0
Δ H° O₂ = 0
Putting in the above equation ,
ΔH rxn = ( 2 * Δ H° (Fe₂O₃ )) - 0
ΔHrxn = 2× - 824.2 kJ / mol = - 1648.4 kJ/mol
- 1648.4 kJ/mol , this much heat is released by the buring of 4 mol of Fe.
Hence ,
for 1 mol of Fe ,
- 1648.4 kJ/mol / 4 = 412.1kJ
I'm pretty sure its an electron. I hope this helps! (:
Answer:
Sulfur dioxide is a covalent bond because we have two non-metals (Sulfur and Oxygen).
(<em>Sulfur dioxide formula)</em>
It's called Sulfur dioxide but it can be called Sulfurous anhydride and Sulfur (lV) oxide.
Sulfur dioxide can have different reactions:
-
In the presence of oxygen oxidation of sulfur dioxide to sulfur trioxide occurs and the formula is:
The equal is because it's a reversible equation. This reaction is spontaneous.
- The sulfur trioxide reacting with water produces sulfuric acid. The formula is:
- Also the sulfur dioxide reacting with sodium hydroxide produces sodium sulfite and the formula is:
- And finally we have the reduction of sulfur dioxide (it can be in presence of hydrogen sulfide) getting elemental sulfur and water. The formula is:
Answer:
0.25 mole of H₂
Explanation:
The equation for the reaction is given below:
Mg + 2HCl —> MgCl₂ + H₂
From the question given above, we were told that the reaction produced 5.6 L of H₂.
Thus, we can obtain obtain the number of mole of H₂ that occupied 5.6 L at STP as follow:
1 mole of H₂ occupied 22.4 L at STP.
Therefore, Xmol of H₂ will occupy 5.6 L at STP i.e
Xmol of H₂ = 5.6 / 22.4
Xmol of H₂ = 0.25 mole
Therefore, 0.25 mole of H₂ were obtained from the reaction.