How many 2-digit numbers can be formed from the digits 1 through 8 if each digit is only used once?
2 answers:
Answer:
56.
Step-by-step explanation:
That is the number of permutations of 2 from 8
= 8P2
= 8!/(8-2)!
= 8!/6!
= 8 * 7
= 56.
Answer:57
Step-by-step explanation:
12
13
14
15
16
17
18
21
23
24
25
26
27
28
31
32
34
35
36
37
38
41
42
43
45
46
47
48
51
52
53
54
56
57
58
61
62
63
64
65
67
68
71
72
73
74
75
76
78
81
82
83
84
85
86
87
..
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Answer:
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Step-by-step explanation:
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