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PilotLPTM [1.2K]

2 years ago

11

Which number is written in scientific notation? 6 times 10 Superscript 11 12 times 10 Superscript negative 8 0.2 times 10 Supers

cript 5 8 times 7 Superscript 2

2 answers:

aliina [53]2 years ago

7 0

Answer:

6 x 10 superscript 11

Step-by-step explanation:

Scientific notation is in the form ;

A.0 x ,

where :

A = any number from 1 to 9

n = integers , that is , n must be whole numbers

Following this rule , the correct answer is

6 x

which is 6 times 10 Superscript 11

Mandarinka [93]2 years ago

5 0

Answer: 6 times 10 Superscript 11

Step-by-step explanation:

Scientific notation is in the form ;

A.0 x $10^{n}$ ,

where :

A = any number from 1 to 9

n = integers , that is , n must be whole numbers

Following this rule , the correct answer is

6 x $10^{11}$

which is 6 times 10 Superscript 11

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–6 < 2x – 4 < 4 solve the inequality

Ira Lisetskai [31]

Answer:

The answer is

<h2> $- 1 < x < 4$ </h2>

Step-by-step explanation:

<h3> $- 6 < 2x - 4 < 4$ </h3>

First of all add 4 to both sides of the inequality to make 2x stand alone

That's

<h3> $- 6 + 4 < 2x - 4 + 4 < 4 + 4 \\ - 2 < 2x < 8$ </h3>

Divide both sides of the inequality by 2 inorder to find x

That's

<h3> $\frac{ - 2}{2} < \frac{2x}{2} < \frac{8}{2}$ </h3>

We have the final answer as

<h3> $- 1 < x < 4$ </h3>

Hope this helps you

6 0

2 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

2 years ago

What is the length of EF in the triangle? Show your work. HELP!

Zinaida [17]

The length of EF in the given triangle is 8.80 m.

Step-by-step explanation:

Step 1:

In the given triangle, the opposite side's length is 16.2 m, the adjacent side's length is x m while the triangle's hypotenuse measures 16.2 m units.

The angle given is 90°, this makes the triangle a right-angled triangle.

So first we calculate the angle of E and use that to find x.

Step 2:

As we have the values of the length of the opposite side and the hypotenuse, we can calculate the sine of the angle to determine the value of the angle of E.

$sinE = \frac{oppositeside}{hypotenuse} =\frac{13.6}{16.2} = 0.8395.$

$E = sin^{-1} (0.8395), E = 57.087.$

So the angle E of the triangle DEF is 57.087°.

Step 3:

As we have the values of the angle and the hypotenuse, we can calculate the cos of the angle to determine x.

$cos E = \frac{adjacentside}{hypotenuse} = \frac{x}{16.2} .$

$cos(57.087) = 0.5433, x = 16.2 (0.5433) = 8.8014.$

Rounding this off to the nearest hundredth, we get x = 8.80 m.

8 0

2 years ago

Suppose that x and y vary inversely and that y = 5 when x = 1. What is y when x = 15?

LiRa [457]

Answer:

Y=1/3

Step-by-step explanation:

X=k/y

So let's make k the subject of formula

k=xy

x=1,y=5

So let's substitute

k=1×5

k=5

So we are to determine the value for y when x is 15

So let's solve

Y=k/x

Y=5/15

Y=1/3

Y=0.333333~0.3

7 0

2 years ago

Can someone solve my homework questions please ?

gulaghasi [49]

A is not congruent
B is not congruent
C is congruent
D is not congruent
E is congruent
Is congruent

4 0

2 years ago