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2 years ago

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Riley bought a plant and planted it in a pot near a window in her house. The initial height of the plant was 6 inches and it gre

w at a rate of 2 inches per month. Write an equation for H,H, in terms of t,t, representing the height, in inches, of the plant tt months after Riley bought the plant.

1 answer:

Softa [21]2 years ago

5 0

Answer:

haha thanks for the points btw the answer is. h2t=th6

Step-by-step explanation:

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The following table shows the length and width of two rectangles:

faltersainse [42]

The perimeter of these can be found by adding length and width and then multiplying by two.

Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6

And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8

So it would be C.

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2 years ago

(10.01 MC) Marko is playing the video game Fort Attack. The purpose of the game is to shoot invading bandits that are trying to

rusak2 [61]

Angle of fire in degrees = 90 + 30 =120 degrees

Angle of fire radians =180 degrees = π

120* π/180=120π /180 OR 4π/6 OR 2π/3

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2 years ago

Read 2 more answers

On 12/31/18, Hite Industries reported retained earnings of $475,000 on its balance sheet, and it reported that it had $135,000 o

olganol [36]

Answer:

Dividends = $105000

So option (c) will be correct answer

Step-by-step explanation:

We have given that Retained earning on 12/31/18 is $475000

And retained earning on 12/31/18 is $445000

Net income = $135000

Change in retained income = $475000-$445000 = $30000

We have to find dividends

We know that dividends is given by

Dividends = net income - change in retained income = $135000-$30000 = $105000

So option (c) will be correct answer

7 0

2 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

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2 years ago

the width of a rectangle is 2 units less than the length. the area of the rectangle is 63 units.what is the length, in units, of

Mice21 [21]

Answer: 9

Step-by-step explanation:

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