As momentum / time = force
so; time = 100÷15
so your answer is 6.7 !!
Answer:
(a) 89 m/s
(b) 11000 N
Explanation:
Note that answers are given to 2 significant figures which is what we have in the values in the question.
(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.
(b) The tension, , is given by
where is the speed, is the tension and is the mass per unit length.
Hence,
To determine , we need to know the mass of the cable. We use the density formula:
where is the mass and is the volume.
If the length is denoted by , then
The density of steel = 8050 kg/m3
The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is
The answer is D. Because the boy jump 3 high
Your experiment should keep one thing constant and measure the other. So vary the temp and measure the pressure. You will get a set of data that relates pressure with temp.
<span>PV = nRT
So
P and T are directly proportional.
</span>These experiments are one of either Boyle-Mariottte's, Gay-Lussac'a or Charles' law.
The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".
According to the question,
Mass of box A,
Mass of box B,
Horizontal force,
From the Newton's law,
→
or,
→
Bu substituting the values, we get
→
→
→
We can see that between the two boxes, the action-reaction pair exist.
then,
→
→
→ (magnitude)
Thus the above solution is appropriate.
Learn more about the magnitude here:
brainly.com/question/13545862