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3 years ago

Can someone help me find the perimeter

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

8 0

Answer: (-1,0)

Step-by-step explanation:

I just wanted to finally help someone

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The positive square root of 72 lies between what pairs of integers?

Softa [21]

The square root of 72 lies between 8 and 9

6 0

2 years ago

Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)

Klio2033 [76]

Answer:

$(g\circ h)(x)=-x^2-x-3$

Step-by-step explanation:

So we have the two functions:

$g(x)=-x-3\text{ and } h(x)=x^2+x$

And we want to find:

$(g\circ h)(x)$

This is the same thing as:

$=g(h(x))$

So, substitute h(x) into g(x):

$g(x)=-x-3\\g(h(x))=-(x^2+x)-3$

Distribute the negative:

$g(h(x))=-x^2-x-3$

And we're done!

So:

$(g\circ h)(x)=-x^2-x-3$

6 0

2 years ago

Read 2 more answers

Find the unknown side length x.

Ganezh [65]

Answer:

x = $\sqrt{65}$

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

$4^{2}$ + $7^{2}$ = $x^{2}$

16 + 49 = $x^{2}$

65 = $x^{2}$

x = sq rt 65

6 0

2 years ago

50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

ozzi

Answer:

c = 8.9 or 4√5

Step-by-step explanation:

5 0

1 year ago

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Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.

Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0

2 years ago

Can someone help me find the perimeter​

Can someone help me find the perimeter