Answer:
In common scientific notation, any nonzero quantity can be expressed in two parts: sufficient whose absolute value is greater than or equal to 1 but less than 10, and a power of 10 by which the coefficient is multiplied. In some writings, the coefficients are closer to zero by one order of magnitude. In this scheme, any nonzero quantity is expressed in two parts: a coefficient whose absolute value is greater than or equal to 0.1 but less than 1, and a power of 10 by which the coefficient is multiplied. The quantity zero is denoted as 0 unless precision is demanded, in which case the requisite number of significant digits are written out
Answer: 280 = x
Step-by-step explanation: Okay you are using this equation! y = kx But you must rearrange it!
When rearranged you get y/x = k
Plug in x and y!
y/x = k
35/140 = k
0.25 = k
Now find the value of x.
You use this formula now, y/k = x
Plug in k from the last problem and y = 70
y/k = x
70/0.25 = x
280 = x
The answer is: " 40 books " .
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Explanation:
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Let "x" equal the number of books that Jill started with. Solve for "x" :
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x – (1/2)x + 16 = 36 ;
1x – (1/2)) = (1/2)x ;
(1/2)x + 16 = 36 ;
Subtract "16" from EACH SIDE of the equation:
(1/2)x + 16 – 16 = 36 – 16 ;
(1/2)x = 20 ;
Multiply each side of the equation by "2" ;
2*(1/2)x = 20 * 2 ;
to get: x = 40 .
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The answer is: " 40 books " .
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To find the mean:
Take <span>3 4 5 3 4 5 6 5 4 3 2 3 4 5 6 4 8 4 3 2 and add them all together
=83
Now you divide 83 by the number of terms in the sample set, which is 20.
83/20 = 4.15
For rounding to the nearest tenth, look at the hundredths space, which is 5. Since it is 5 or higher, round the tenths up one.
final answer= 4.2 </span><span />
Answer:
2.9 in.
Step-by-step explanation:
Let x in be the width of the larger rectangle. If the length of the larger rectangle is 4 inches and the perimeter of the larger rectangle is 14 in, then
If two rectangles are similar, then their lengths and widths are proportional with the scale factor k. Thus, the length of the smaller rectangle is in and the width of the smaller rectangle is in. If the perimeter of the smaller rectangle is 10 in, then