Answer:
26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃
Explanation:
To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?
moles of O₂= 26.25 ≅ 26.3
<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>
Answer:
The answer is "0.35".
Explanation:
please find the complete question in the attached file.
Mass of 
Molar mass of 
No of moles in 
Mass of water 
The molar mass of water 
moles of water 
:
Molfraction of acetic acid:
Answer:
83.9g of sulfuric acid is the minimum mass you would need
1.73g of hydrogen would be produced
Explanation:
Based on the reaction:
2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)
2 moles of solid aluminium react with 3 moles of sulfuric acid. Also, two moles of Al produce 3 moles of hydrogen gas.
15.4g of Al are:
15.4g Al × (1mol / 26.98g) = 0.571 moles of Al.
Moles of sulfuric acid:
0.571 moles Al × (3 mol H₂SO₄ / 2 mol Al) = 0.8565 moles H₂SO₄
In grams:
0.8565 moles H₂SO₄ × (98g / 1mol) = <em>83.9g of sulfuric acid is the minimum mass you would need</em>
In the same way, moles of hydrogen produced are:
0.571 moles Al × (3 mol H₂ / 2 mol Al) = 0.8565 moles H₂
In grams:
0.8565 moles H₂ × (2.015g / 1mol) = <em>1.73g of hydrogen would be produced</em>
