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2 years ago

Why is it advisable to keep the storage bottle containing the naoh solution closed?

1 answer:

5 0

The pure form of sodium hydroxide is solid. Compared to the pure form, the aqueous form of the liquid is actually many times more volatile. For this very reason, it is advised that the bottles used to keep samples of NaOH be kept closed.

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100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

kap26 [50]

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

$\frac{M1V1}{V2} = M2$

$\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M$

4 0

2 years ago

Помогите срочно сделать по химии промежуточную отестацию за 8 класс

il63 [147K]

Answer:

This is site for English speakers. Этот сайт на английском, поэтому вопрос могут удалить

Explanation:

1. 2)

2. 3)

3. 4) Sr

4. 3)

5. 4)

6. 2)

7. 1)

8. 4)

9. 3)

10. 3)

11. SO3, H2SO4, Na2SO4

12.

A) оксид меди (II) 2) CuO

Б) хлорид меди(II) 4) CuCl2

В) сульфит меди (II) 3) CuSO 3

Г) гидроксид меди (II) 1) Cu(OH)2

13.

1. Fe+HCl= б) FeCl 2 +H 2

2.Fe+O2= в) Fe 3 O 4

3. Fe(OH) 3 = г)Fe 2 O 3 +H 2O

4. FeCl 2 +NaOH= а) Fe(OH) 2 +NaCl

14. 2Ca + O2 = 2CaO

CaO + H2O = Ca(OH)2

Ca(OH)2 + 2HCl = CaCl2 + 2H2O

6 0

2 years ago

: Question List

Ira Lisetskai [31]

Potassium it is the answer

6 0

2 years ago

The diagram below shows a longitudinal wave at one instant in its motion. Each oval represents a particle acted on by the ener t

Anton [14]

Answer:

the first line

Explanation:

A rarefaction is a region in a longitudinal wave where the particles are furthest apart. ... The region where the medium is compressed is known as a compression and the region where the medium is spread out is known as a rarefaction.

use this picture as a reference:

8 0

2 years ago

Read 2 more answers

Enough of a monoprotic weak acid is dissolved in water to produce a 0.0172 M solution. If the pH of the resulting solution is 2.

Mumz [18]

Answer:

9.7 x 10⁻⁴

Explanation:

HA ⇄ H⁺ + A⁻

C(eq) 0.0174 10⁻²·³⁹ 10⁻²·³⁹

=0.0041M =0.0041M

Ka = [H⁺][A⁻]/[HA] = (0.0014)²/(0.0174) = 9.7 x 10⁻⁴

8 0

2 years ago