The answer will help you.
<span><span><span><span>13x</span>−<span>5x</span></span>+6</span>=<span>6+<span>8x
</span></span></span><span><span><span><span><span>13x</span>+</span>−<span>5x</span></span>+6</span>=<span>6+<span>8x
</span></span></span><span><span><span>(<span><span>13x</span>+<span>−<span>5x</span></span></span>)</span>+<span>(6)</span></span>=<span><span>8x</span>+<span>6
</span></span></span><span><span><span>8x</span>+6</span>=<span><span>8x</span>+6
</span></span><span><span><span>8x</span>+6</span>=<span><span>8x</span>+<span>6
</span></span></span><span><span><span><span>8x</span>+6</span>−<span>8x</span></span>=<span><span><span>8x</span>+6</span>−<span>8x
</span></span></span><span>6=6
</span><span><span>6−6</span>=<span>6−6
</span></span><span>0=<span>0
It has a real numbers are solutions.
And the answer is A.</span></span>
3: m= 2, -3
4: x= -1, 5/2
5: x= -1, -3
6: x= 5/2, -4
Answer:
The approximate measure of angle K is 34°
Step-by-step explanation:
In ΔJKL
∠L = 105°
JK = 4.7
JL = 2.7
Sine Rule:
So,
K ≈ 34°
So, Option B is true
Hence The approximate measure of angle K is 34°
Answer: 4 inches
Step-by-step explanation:
Let the width of the pool in the drawing be represented by x.
Since scale drawing of a pool has scale of 1 in :4 ft and the actual pool is 16 ft wide, this can be represented in an equation as:
1/4 = x/16
Cross multiply
4 × x = 1 × 16
4x = 16
x = 16/4
x = 4
Therefore, the pool representation in the drawing is 4 inches
Answer: slope= 6
Slope intercept equation= y= 6x +2
Step-by-step explanation:
Slope formula: (y2 - y1) ÷ (x2 - x1) > (-4-8) ÷ (-1-1) = -12/-2 or 6
Plug slope (-6) and one coordinate into point slope form: y-1=m (x-1)
where m is slope and (1,8) would be (x,y)
Y-8= 6(x-1) > y-8 = 5x -6 > y= 6x +2
