Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
Answer:
Step-by-step explanation:
Assuming this is a linear equation in the form of , we can first solve for the slope using , for these points, the slope would be . Now we plug in the points to get the equation:
plugging in (7,5), we get × +
and solving for b, we get b =
therefore, the equation of the line passing through (7,5) and (1,2) is .
hope this helps!
Answer:
120 minutes
Step-by-step explanation:
1 hour = 60 min
2x = answer
x = 60
2 (60) = 120
Answer = 120 minutes
Answer:
0, 1, 2
Step-by-step explanation:
So, since there are three consecutive integers, you have the equations
x, x+1, x+2 where x is the smallest number.
The greatest of the three integers= x+2
Finish setting up your equation;
2(x+x+1)=x+2
Combine like terms;
2(2x+1)=x+2
Distribute;
4x+2=x+2
3x=0
x=0
x+1=1
x+2=2
Hope this helps:) Have a good day!