Explanation:
The given data is as follows.
Length of beam, (L) = 5.50 m
Weight of the beam, () = 332 N
Weight of the Suki, () = 505 N
After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.
= 0
x =
=
= 0.986 m
Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.
Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.
Answer:
The resistance of the inductor at resonance is 258.76 ohms.
Explanation:
Given;
resistance of the resistor, R = 305 ohm
capacitance of the capacitor, C = 1.1 μF = 1.1 x 10⁻⁶ F
inductance of the inductor, L = 42 mH = 42 x 10⁻³ H = 0.042 H
At resonance the inductive reactance is equal to capacitive reactance.
Where;
F₀ is the resonance frequency
The inductive reactance is given by;
Therefore, the resistance of the inductor at resonance is 258.76 ohms.
Answer:
Velocity = 0.0001389 m/s
Explanation:
Given that the
Distance covered = 1 metre
Time taken = 2 hours
Convert the hour to second
1 hour = 60 × 60 = 3600
2 hours = 2 × 3600 = 7200
What is the velocity of a worm moving 1 meter in 2 hours to the East?
Velocity can be referred as speed.
Velocity = distance/ time
Velocity = 1/7200
Velocity = 0.0001389 m/s
Answer: 6 times further
Explanation:
Initial velocity is the same that she uses on earth vertically and horizontally
Vertically we can say
V = -g t
If g is 1/6 earth gravity, then t is 6 times earth time.
Then, horizontally, with the same initial time, no incidence of gravity and knowing t
X= v t
Distance in the moon is 6 times distance in the earth.