The correct question is
Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:
Na3[CoCl6]
[Ni(CO)4]
[Ni(NH3)3(H2O)2] (NO3)2
Answer:
See explanation for details
Explanation:
Na3[CoCl6]
Name: Sodium hexacholorocobalt III
Charge on the complex: -3
Central metal ion name : cobalt III
coordination number: 6
[Ni(CO)4]
Name: tetracarbonyl nickel (0)
Charge on the complex: 0
Central metal ion name : nickel (0)
coordination number: 4
[Ni(NH3)3(H2O)2] (NO3)2
Name: Diaquatriaminenickel II nitrate
Charge on the complex: +2
Central metal ion name : nickel (+2)
coordination number: 5
Mass percent= grams solute/ grams of solution x 100
Mass Percent= (50/ 150)x100= 33.3%
Depression of a freezing point of the solutions depends on the number of particles of the solute in the solution.
1 mol of C6H12O6 after dissolving in water still be 1 mol, because C6H12O6 does no dissociate in water.
1 mol of C2H5OH after dissolving in water still be 1 mol, because C2H5OH does no dissociate in water.
1 mol of NaCl after dissolving in water gives 2 mol of particles (ions), because NaCl is a strong electrolyte(as salt) and completely dissociates in water.
NaCl ----->Na⁺ + Cl⁻
1 mol of CH3COOH after dissolving in water gives more than 1 mol but less than 2 moles, because CH3COOH is a weak electrolyte (weak acid) and dissociates only partially.
So, most particles of the solute is going to be in the solution of NaCl,
so<span> the lowest freezing point has the aqueous solution of NaCl.</span>
The new concentrations of and are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of = number of moles/volume in lit = 0. 500 M
Number of moles = molarity of × volume in lit = 0. 500 M× 0.025 L
Number of moles of = 0.0125 mole
Molarity of = number of moles/volume in lit = 0. 38 M
Number of moles = molarity of × volume in lit = 0. 38 M× 0.025 L
Number of moles of = 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of = number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of = 0.25M
Molarity of = number of moles/volume in lit = 0.95mole/0.05L
Molarity of = 19 M
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c
Explanation:
pay attention in class next time bye hope it helps THE ANSWER IS C bye