We can solve with a system of equations, and use c for the amount of cans of soup and f for the amount of frozen dinners.
The first equation will represent the amount of sodium. We know the (sodium in one can times the number of cans) plus (sodium in one frozen dinner times the number of dinners) is the expression for the total sodium. We also know the total sodium is 4450, so:
250c + 550f = 4450
The second equation is to find how many of each item are purchased:
c + f = 13
Solve for c in the second equation:
c = 13 - f
Plug this in for c in the first equation:
250(13-f) + 550f = 4450
3250 - 250f + 550f = 4450
300f = 1200
f = 4
Now plug the value for f into the second equation:
c + 4 = 13
c = 9
The answer is 9 cans of soups and 4 frozen dinners.
i think the answer is linear I am not sure though
Answer:Find the GCD (or HCF) of numerator and denominator
GCD of 56 and 100 is 4
Divide both the numerator and denominator by the GCD
56 ÷ 4
100 ÷ 4
Reduced fraction:
14
25
Therefore, 56/100 simplified to lowest terms is 14/25
Step-by-step explanation:
hope this helps have a great day
Answer:
Step-by-step explanation:
6 and 3/4 shorter pieces
36 in =1yd
36*3=
Well 6*3= 18 carry the 1 then u have 3*3+1=10
Then that equals 108. So u have to dived next,
16/108=
This next step u have to do long division,
Put 16 on the outside and then put 108 in the inside, then ask yourself can 16 go int 10 it can’t, than u have 108 can this go into 16 yes it can go into 6 times so ur reminder is 12
16 divided by 4 over 12 divided by 4 = 4 over 3
4 divided by 3 = 1
4 divided by 3 = 1 1/3- this can reduced so
4 divided by 3 = 1.3333333 is ur answer
