Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Step 1: 6x - 2x - 5 = -6 + 21
Step 2: 6x - 2x - 5 = 15
Step 3: 4x - 5 = 15
The next step would be to add 5 to both sides of the equation.
so Step 3: 4x - 5 = 15 .......add 5 to both sides would make
Step 4: 4x = 20
So after the next step you would have 4x = 20
Hope this helps! :)
Answer: 5x 5y
Step-by-step explanation: because of the length
Answer:
135.5ft
Step-by-step explanation:
THIS COMPLETE THE QUESTION
flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.
Let X be the length of the wire
Let y be the height of the pole
X= Y + 14
Y= X -14
We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)
Using Pythagoras theorem
X²= 60² + Y²
X² = 3600 + Y²
if we subsitute for Y we have
X² = 3600 + (X -14)²
X² = 3600 +X² -14X-14X+196
X²-X²+ 28X= 3600+196
28X= 3796
X= 3796/28
=135.5ft
hence length of the wire is 135.5ft