Answer: The proportion that will qualify is 0.0314 or 3.14%.
First, we need to find the z-score of a time of 128 seconds. To do this, we find the difference of the mean and score and divide by the standard deviation.
(128 - 141) / 7 = -1.86
Now, use a standard normal distribution table to determine the percent below a z-score of -1.86. That value is 0.0314 or 3.14%.
Answer: alternative D.
Step-by-step explanation: The two correct alternatives are A and B, which state that a larger sample would fit into the 95% confidence interval with a smaller margin of error, since<u> the more samples, the less is the deviance from its calculated average value</u>. If the sample size is bigger and the margin of error smaller, the tendency to choose randomly one individual and having a result closer to the true value of the average hormone level increases.
Answer:
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It looks like it goes through (0,-3) and (1,2), so the gradient is (change in y)/(change in x) ->
(-3-2)/(0-1) = 5
So y=5x+b
Then as we know it passes the y axis at (0,-3) so b= -3
So we have y=5x-3