Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :
For minimum P,
SO, it is a square.
Therefore, the dimensions are .24\sqrt{3}
Hence, this is the required solution.
Answer:
X = -2, Y = 13
X = 0, Y = 9
X = 2, Y = 5
X = 4, Y = 1
Step-by-step explanation:
Take the value given for X and plug it into the equation. For example, when X = -4, you will make your equation look as follows:
y = -2(-4) + 9
Simplify it:
y = 8 + 9
y = 17
Repeat this process with the rest of the X values to get your Y values.
A) your money
hope this is right!
please let me know
Answer:
See Below:
Step-by-step explanation:
40,000*8/25= the diameter, because the diameter is 8/25 of the equator which is 40000
Diameter= 40,000*8/25
Diameter= 12,800 km
Complementary angles add to 90 degrees. This means that 65 + x = 90, so x = 90 - 65 = 25.