Given f(x)=4x^2−5 and g(x)=x+3 . What is (fg)(x) ?

Mathematics

2 answers:

zmey [24]2 years ago

4 0

(fg)(x)=f(g(x))=4(g(x))²-5=4(x+3)²-5=4x²+24x+31

Yuki888 [10]2 years ago

4 0

(fg)(x) = f(g(x))
= 4(x+3)^2 − 5
= 4(x^2 + 6x + 9) - 5
= 4x^2 + 24x + 36 - 5
= 4x^2 + 24x + 31

answer
(fg)(x) = 4x^2 + 24x + 31

You might be interested in

What does set up a proportion and solve mean

alina1380 [7]

Set up fractions and solve them

7 0

2 years ago

Please please help me. i’ll literally send you money. i need to pass please help

mihalych1998 [28]

<h3>Answer: Approximately 6.4 units</h3>

==================================================

Explanation:

The origin is the point (0,0)

Use the distance formula to find the distance from (0, 0) to (4, -5)

Let

$(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\$

be our two points. Plug those values into the distance formula below and use a calculator to compute

$d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\$