Answer:
<h2>How many car accidents involve airbag malfunctions?</h2><h2 />
This is because there's no need to survey an entire population for accurate results.
The other 3, regarding Colorado residents, middle school students, and classmates are considered a population.
For testing the amount of car accidents, a population is not needed.
<em />
<em>I hope this helped you!</em>
<span>You forgot to tell us how much the tickets cost each.
So I just arbitrarily chose that the price of a student
ticket is $4 and the price of a non-student ticket is $6.
<span>Let the number of student tickets be x
Let the number of non-student tickets be y
Price Money
Type Number of from
of of EACH ALL
ticket tickets ticket tickets
-------------------------------------------
student x $4 $4x
non-student y $6 $6y
-------------------------------------------
TOTALS 48 ----- $220
The first equation comes from the second column.
x + y = 48
The second equation comes from the last column:
4x + 6y = 220
So we have this system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 48
y = 48 - x
Substitute (48 - x) for y in 4x + 6y = 220
4x + 6(48 - x) = 220
4x + 288 - 6x = 220
-2x + 288 = 220
-2x = -68
x = 34 = the number of student tickets.
Substitute in y = 48 - x
y = 48 - (34)
y = 14 non-student tickets.
Checking: 34 student tickets brings in $136 and 14 non-students is $84
That's 48 tickets.
And indeed $136 + $84 = $220
</span>
</span>
The expression given in the question can be simplified by getting them out of the brackets and then adding and subtracting the like terms. This will yeild the desired result.
<span>(-1+6i)+(-4+2i) = - 1 + 6i - 4 + 2i
= -5 + 8i
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the third option or option "c".</span>
