Answer:
y = 0.5 (x^2 -2x + 16) has a y-intercept of 8.
Step-by-step explanation:
The x-coordinate of every y-intercept is zero. To determine which of the four quadratics given here has a y-intercept of 8, we need only substitute 0 for x in each; if the result is 8, we've found the desired quadratic.
O y = 0.5(x + 2)(x + 4) becomes y = 0.5(2)(4) = 4 (reject this answer)
O y = 0.5 (x - 2)(x + 8) becomes y = 0.5(-2)(8) = -8 (reject)
O y = 0.5(x2 -2x - 16) becomes y = 0.5(-16) = -8 (reject)
<em>O y = 0.5 (x2 -2x + 16) becomes y = 0.5(16) = 8 This is correct; that '8' represents the y-intercept (0, 8).</em>
Answer: D
-2.9a+6.8+4.4a-7.3
[-2.9a+4.4a]=1.5a
[6.8-7.3]=-0.5
1.5a-0.5
Umm maybe try:
f^-1 (x) = -4x/3 + 32/3
let me know if that’s right
Answer:A negative number divided by a positive number is always negative
Step-by-step explanation:
