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2 years ago

20 POINTS !! PLEASE ANSWER THIS MATH QUESTION !!

Mathematics

2 answers:

Semmy [17]2 years ago

6 0

Answer:

7.8

Step-by-step explanation:

Sine 50=6/x

x= 6/Sine 50

x=7.8

andrew-mc [135]2 years ago

4 0

Answer:

h ≈ 7.8 cm

Step-by-step explanation:

Use sines to determine the length of the hypotenuse. You know that there is a 50 degree angle, and that the ratio for sine is opposite/hypotenuse. You know that the opposite side from that angle is 6 cm, so you can set up the following equation:

sin50 = 6/h

sin50h = 6

h ≈ 7.8 cm

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HELP !!! What is the center of the circle? A. (-2,0) B. (3,-1) C. (-3,4) D. (2,-5)

vovangra [49]

Answer:

3, -1

Step-by-step explanation:

because that is the point that is at the center :)

8 0

2 years ago

What are the next 2 words in the pattern? half dollar, quarter, dime...

OleMash [197]

Answer:

Nickel and penny.

Step-by-step explanation:

The given pattern is

half dollar, quarter, dime...

This is a part of the pattern of US coins.

The pattern of US coins in decreasing order is

Dollar, half dollar, quarter, dime, nickel, penny.

It is clear that the next 2 words in this pattern after dime are nickel and penny.

Therefore, the required 2 words are nickel and penny.

8 0

3 years ago

The perimeter of a rectangle is 126 inches. The length is 7 less than 4 times the width. Find the dimensions of the rectangle. P

motikmotik

I hope someone solves your problem :)

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2 years ago

An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How

AleksAgata [21]

Answer:

6 days

Step-by-step explanation:

Let the time taken by Carpenter working alone = $C$ days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 $C$ days

Time taken working together = 2 days

Work done in one day working together = $\frac{1}{2}$

Work done in one day by Carpenter working alone = $\frac{1}{C}$

Work done in one day by apprentice working alone = $\frac{1}{2C}$

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = $\frac{1}{C}$ + $\frac{1}{2C}$ = Work done in one day working together = $\frac{1}{2}$

$\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days$