All categories

2 years ago

Math question down below

Mathematics

2 answers:

Vilka [71]2 years ago

6 0

The answer is c, 30/7

olganol [36]2 years ago

4 0

The answer would be 30 over 7

You might be interested in

Virginia bought 18 packs of envelopes for $2 each and 15 packs of thank you cards for $4 each . if she gives the cashier $100, h

dolphi86 [110]

She would get 4 dollars back because 15 times 4 is 60 and 18 tomes 2 is 36 add them and you get 96 subtract 96 from 100 and 4

5 0

2 years ago

Geometry, help !!!

MAVERICK [17]

Of an obtuse?8,11 and 15

3 0

2 years ago

Please help urgent!!

USPshnik [31]

Answer:

$Q M \cong R M \Rightarrow$ definition of midpoint

$\overline{P M} \cong \overline{P M} \Rightarrow$ Reflexive property of congruence

$\Delta P Q M \cong \Delta P R M \Rightarrow$ SSS congruence postulate

$\angle Q \cong \angle R \Rightarrow$ CPCTC theorem

Step-by-step explanation:

Step 1: Since, M is the midpoint of the line segment QR.

$\overline{Q M} \cong \overline{R M} \Rightarrow$ definition of midpoint

Step 2: The reflexive property of congruence states that a line segment or an angle or a shape is always equal to itself.

$\overline{P M} \cong \overline{P M} \Rightarrow$ Reflexive property of congruence.

Step 3: The SSS congruence postulate states that if three sides of a triangle are equal to three sides of another triangle, then the two triangles are congruent.

$\Delta P Q M \cong \Delta P R M \Rightarrow$ SSS congruence postulate

Step 4: CPCTC theorem states if two triangles are congruent then the sides and angles are also congruent.

$\angle Q \cong \angle R \Rightarrow$ CPCTC theorem.

3 0

2 years ago

Perform each indicated operation

MissTica

Answer: $\frac{x+6}{x-4}$

Step-by-step explanation:

First you need know some general formuals of factorization such as

$x^3+y^3=(x+y)(x^2-xy+y^2)$ so you have $x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)$

And, $x^2-y^2=(x-y)(x+y)$ so you have $2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)$

If you use them, then you can modify your equations such as

$\frac{x^3+64}{2x^2-32}$ ÷ $\frac{x^2-4x+16}{2x+12}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)}$ ÷ $\frac{x^2-4x+16}{2(x+6)}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} . \frac{2(x+6)}{{x^2-4x+16}} = \frac{1}{x-4}.\frac{x+6}{1}=\frac{x+6}{x-4}$