circumference = 2 x pi x r
using 3.14 for pi
2 x3.14x114=715.92
round to 716 yards
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
Answer:
Part A: He can use distance formula. The formula is:
Part B: 41.63 (rounded to nearest hundredth)
Step-by-step explanation:
Plug this into the formula. First, subtract the numbers in the parentheses. Then, square them. Add those totals together. Lastly, take the square root using a calculator.
Answer:
A. (-∞, ∞)
Step-by-step explanation:
f circle g (x) is another way of expressing f(g(x)). Basically, we have to plug g(x) into f(x) wherever we see x's.
f(x) = x^2 - 1
f(x) = (2x-3)^2 - 1
Now find the domain. I think the easiest way to do this is to graph it. I've attached the graph. You can also do it algebraically by thinking about it: it's a positive parabola (+x^2) and its minimum is -1, so its range will not be all real numbers, but its domain will certainly be. (The range would be answer choice B!)
Domain = (-∞, ∞)