2 years ago

If you have 3/4 cup of flour how many eigths do you have

Mathematics

1 answer:

Nina [5.8K]2 years ago

4 0

Your answer to the problem is 6/8

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What is four hundred eight thousand,seventeen in standard form and expanded form?

mestny [16]

408,017 is in standard form and
400,000+8,000+10+7=408,017 is expanded form
sixty five thousand and fifty eight is word form
60,000+5,000+50+8=65͵058 is expanded form

6 0

2 years ago

Read 2 more answers

7. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point) f(g(x)) = 2 Square root of quantity two

AlladinOne [14]

Answer:

f(g(x)) =

$\sqrt{8x \: - \: 13} \: + \: 9$

Step-by-step explanation:

f(x) =

$\sqrt{x} \: + \: 9$

g(x) = 8x - 13

f(g(x) =

$\sqrt{8x \: - 13} \: + \: 9$

5 0

2 years ago

2. Solve the equation. (50 Points) * = + 9 = 30 Enter your math answer

barxatty [35]

Answer:

x= 42

Step-by-step explanation:

x/2+9=30

x+18=60

x=60-18

x= 42

5 0

2 years ago

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Help me please for 10pt

balandron [24]

Answer:

The answer is A

Step-by-step explanation:

6 0

2 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable X represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

2 years ago