Answer:
Explanation:
e = Charge of electron = 
n = Electron concentration = 
= Drift veloctiy = 113 m/s
E = Electric field = 510 V/m
Electron mobility is given by
Conductivity is given by
The conductivity of this material is
They compare the structure of the organisms, and they use the information about the chemical makeup of the organisms cells.
The frequency<span> of oscillation of the dot is the </span>frequency<span> #f# of the </span>wave<span>. The second </span>wave<span> has twice the </span>frequency<span> of the first. </span>You<span> can see that the </span>wavelength<span>is halved when the </span>frequency<span> is doubled. Since #v# is constant, </span>if<span> #f# increases, #λ# must decrease, and vice versa</span>
Answer:
Given:
m=1000kg
F=8000 N
u=32m/s
v=0m/s
Required:
T=?
Solution:
F=m × a
8000N = 1000kg × a
a = 8m/s^2
Since it's deceleration -8m/s^2
a= v - u / t
-8m/s^2 = 0 - 32m/s / T
T = 4 s
Hence the car takes 4sec to stop
Please follow me
Assuming the woman starts at rest, she descends the slide with acceleration <em>a</em> such that
(20.3 m/s)² = 2 <em>a</em> (42.6 m) → <em>a</em> ≈ 4.84 m/s²
which points parallel to the slide.
The only forces acting on her, parallel to the slide, are
• the parallel component of her weight, <em>w</em> (//)
• friction, <em>f</em>, opposing her descent and pointing up the slide
Take the downward sliding direction to be positive. By Newton's second law, the net force in the parallel direction acting on the woman is
∑ <em>F</em> (//) = <em>w </em>(//) - <em>f</em> = <em>ma</em>
where <em>m</em> = 77.0 kg is the woman's mass.
Solve for <em>f</em> :
<em>mg</em> sin(42.3°) - <em>f</em> = <em>ma</em>
<em>f</em> = <em>m</em> (<em>g</em> sin(42.3°) - <em>a</em>)
<em>f</em> = (77.0 kg) ((9.80 m/s²) sin(42.3°) - 4.84 m/s²) ≈ 135 N
Compute the work <em>W</em> done by friction: multiply the magnitude of the friction by the length of the slide.
<em>W</em> = (135 N) (42.6 m) ≈ 5770 N•m = 5770 J
