D would be the highest value
X(^-1)^7=x^6
7(c^1)^2/3=7(c)^2/3
(m^2n^3)^-3=1/m^6n^9
Answer:
0.762 = 76.2% probability that this shipment is accepted
Step-by-step explanation:
For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17 randomly selected pens
This means that
(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)
This is when . So
0.762 = 76.2% probability that this shipment is accepted
Use the zeroes to figure this out... x=-18, y=9