5(-11)+4(3)^2 = -19
The answer is -19
A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
Answer:
Number of terms:3
Degree:2nd degree
Step-by-step explanation:
-5c^2 +8c +2-3
-5c^2 +8c-1
he 2nd degree is the power of 2
<h3>
Answer:</h3><h3> C</h3><h3 /><h3>
Step-by-step explanation:</h3><h3>It is C.</h3>
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