Answer:
X=30
Step-by-step explanation:
y=kx
6=10k
k=0.6
y=0.6x
18=0.6x
X=18/0.6
x=30
The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.
<h3>Equation</h3>
Let
- Size of the first application = x
- Size of the second application= x - 3.45 mb
For instance,
if the size of the first application is 297 MB
Size of the second application= x - 3.45 mb
= 297 MB - 3.45 MB
= 293.55 MB
Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB
Learn more about equation:
brainly.com/question/2972832
#SPJ1
Answer: 140cm 2
Step-by-step explanation: 8 x 5 = 40 x 4 = 115 + 25 = 140
The equation which the civil engineer can use to find the number of rows is 2x² - 12x = 112. Option D
<h3>How to determine the equation</h3>
Let the number of rows be x
Number of cars in each row = x - 6 = 56
Number of rows for parking lot = 2x
Then,
Number of cars for new parking lot = 2x ( x - 6 = 56)
Expand the expression,
2 ( x - 6 = 56)
2x² - 12x = 112
Thus, the equation which the civil engineer can use to find the number of rows is 2x² - 12x = 112. Option D
Learn more about word problems here:
brainly.com/question/1781657
#SPJ1
Answer:
z = 189/44
Step-by-step explanation:
The "varies jointly" relationship can be expressed by ...
y = kxz
We can find k from the given values.
40 = k(10)(9)
40/90 = k = 4/9 . . . divide by the coefficient of k
Now we want to find z for given values of x and y. That can be found from ...
y = (4/9)xz
9y/(4x) = z . . . . . multiply by 9/(4x)
Filling in the new numbers, we have ...
z = 9·105/(4·55)
z = 4 13/44 = 189/44 ≈ 4.2954...(repeating 54)
