Answer:
Mass of the box = 0.9433 kg
Explanation:
Mass of racket-ball = 0.00427 kg
Velocity of racket-ball before collision = 22.3 m/s
Velocity of racket-ball after collision with box = -11.5 m/s
[Since ball is bouncing back, so velocity is taken negative.]
Velocity of the box before collision = 0 m/s
<em>[Since the box is stationary, so velocity is taken zero]</em>
Velocity of box moving forward after collision = 1.53 m/s
To find the mas of the box .
By law of conservation of momentum we have:
Momentum before collision = Momentum after collision
This can be written as:
We can plugin the given value to find
Adding both sides by 0.4911
Dividing both sides by 1.53.
∴ kg
Mass of the box = 0.9433 kg (Answer)
Hello!
By applying the third law of motion, your force and the wall's force are equal.
I hope this helps you! Have a great day!
- Mal
<h3>answer</h3>
The minimum velocity required for a object to rotate in a verticle plane is v
1
=
5
gr.
So, at bottom point, T
max
=mv
1
2
/r+mg=6mg.
At top-most point velocity is v
2
=gr.
So, T
min
=mv
2
2
/r−mg=0
So T
max
−T
min
=6mg=2×g⇒m=1/3 kg
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