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3 years ago

8 (40+7) = ( 8. ) + (8 7

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

The first part is 8 x 40=320
8 x 7=56
320+56 and i am not sure what you have going on on the other half

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Please help with this and explain the answer.

zysi [14]

Answer:

48.06

Step-by-step explanation:

b^2+c^2=A^2

45+16=42.06

add the extra 6

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2 years ago

A water container is 1/8 full. 35 litres if water are now poured into the container. The container is now 1/4 full.

Aloiza [94]

Answer:

<em>The container can hold 280 liters of water.</em>

Step-by-step explanation:

<u>Proportions</u>

The water originally fills 1/8 of a container. Then 35 lt of water are poured into the container and now it's 1/4 full.

If we subtract the final portion of the tank minus the original portion of the container, we obtain the portion that was poured into.

$\mathrm{Portion\ poured }=\frac{1}{4}-\frac{1}{8}=\frac{2}{8}-\frac{1}{8}=\frac{1}{8}$

If 35 liters of water is 1/8 of the tank, then it can hold 35*8 = 280 liters.

The container can hold 280 liters of water.

4 0

2 years ago

Hi, help ASAP please.

Kisachek [45]

Answer:

17.3

Step-by-step explanation:

50 - 32.7 = 17.3

7 0

1 year ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

Heather works part time at a movie theater where she earns $7.00

Nastasia [14]

Answer:

d. 1 grid equals 1 hour

Step-by-step explanation:

When plotting research data, X-axis(or horizontal axis) usually used for independent variable and Y-axis is used for the dependent variable. In this case, Heather wants to know how much earning on different numbers of hours. The dependent variable is the earning and the independent variable is the hours, so you put hours on the horizontal axis.

You want to make a 10x10 grid of data and the hours ranged between 1-10. If you plot them equally, approximate scale will be: (10h-1h)/(10)= 0.9h/grid

The closest option is 1 hour per grid. It will provide the best visualization since it won't stretch or minimize the data too much.

8 0

2 years ago