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12 days ago

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• An object of mass 2.0 kg moves in uniform circular motion on a horizontal friction less table. The radius of the circle is 0.7

5 m and the centripetal force is 10.0 N. The work done by this force when the object moves through one-half of a complete revolution is

1 answer:

Gekata [30.6K]12 days ago

4 0

Answer:

23.562

Explanation:

First it is good to work out the circumference:

2 pi r

2 pi .75

circumference = 4.7124

Next we need half of this because it is half a resolution. This will be our distance travelled.

half = 2.3562

word done = force x distance

work done = 10 x 2.3562

work done = 23.562

(I didn't see the need for mass...)

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