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11 months ago

1 Which is the greatest 4- digit number divisible by 6?......

Mathematics

1 answer:

Alekssandra [29.7K]11 months ago

4 0

Answer:

The greatest four-digit number that is divisible by 6 is 9996

Step-by-step explanation:

9,996 / 6 = 1,666

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High of the following transformations does not result in a congruent figure

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Any transformation involving change of scale will not result in a congruent figure. Rotations and reflections and translations maintain congruence.

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2 years ago

16 The cost for parking at a city airport is shown in the table.

Alexxx [7]

Answer:

He paid $9 twelve times

12× 2= 24 days

Step-by-step explanation:

1st day = $16.60

3rd day=$ 9 (i.e for every 2days afterwards)

5th day=$ 9

Yuri pays : 124.60

124.60-16.60

= $108.00

After paying the first day he paid 108.00

108.00÷ 9 = 12

He paid $9 twelve times

12× 2= 24 days

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2 years ago

Which expressions are not polynomials?

Naddika [18.5K]

Answer:

The middle two expressions shown are not polynomials

Step-by-step explanation:

Polynomial terms have positive integer exponents on any variables. A 2/3 power is not an integer exponent. Division by y is equivalent to an exponent of -1, which is not a positive integer.

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3 years ago

5/6 - 7/12? what is it

IgorLugansk [536]

Answer:

3/10

Step-by-step explanation:

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1 year ago

Read 2 more answers

Square root of 648.7209 by division method

SpyIntel [72]

Answer:

$25.47$

Step-by-step explanation:

This root can be rewritten as:

$\sqrt{\frac{6487209}{10000} }$

$\sqrt{\frac{6487209}{100^{2}} }$

$\frac{1}{100}\cdot \sqrt{6487209}$

Since 6487209 is a multple of 3, the expression can be rearranged as follows:

$\frac{1}{100}\cdot \sqrt{3\times 2162403}$

2162403 is also a multiple of 3, then:

$\frac{1}{100}\cdot \sqrt{3^{2}\times 720801}$

$\frac{3}{100}\cdot \sqrt{720801}$

720801 is a multiple of 3, then:

$\frac{3}{100}\cdot \sqrt{3\times 240267}$

240267 is a multiple of 3, then:

$\frac{3}{100}\times \sqrt{3^{2}\times 80089}$

$\frac{9}{100}\cdot \sqrt{80089}$

80089 is a multiple of 283, then:

$\frac{9}{100}\cdot \sqrt{283^{2}}$

$\frac{9\times 283}{100}$

$\frac{2547}{100}$

$25.47$

6 0

2 years ago

1 Which is the greatest 4- digit number divisible by 6?......​

1 Which is the greatest 4- digit number divisible by 6?......