Question

What is the standard form of a quadratic function passing through the points (2,4) , (3,5) and (4,3)

Answer 1

The standard form of a quadratic function is y = 3/2x² + 17/2x - 7

How to determine the quadratic equation?

From the question, the points on the quadratic equation are given as

(2,4), (3,5) and (4,3)

The standard form of a quadratic equation is represented as

y = ax² + bx + c

So, we have

Point (2,4):

4a + 2b + c = 4

Point (3,5):

9a + 3b + c = 5

Point (4,3):

16a + 4b + c = 3

Solving using an online calculator. we have

a = 3/2, b = 17/2 and c = -7

Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c

y = 3/2x² + 17/2x - 7

Hence, the equation is y = 3/2x² + 17/2x - 7

Read more about quadratic equation at

brainly.com/question/1214333

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