1) given function
y = - 2 ^ ( -x + 2) + 1
2) domain: domain is the set of the x-values for which the function is defined.
The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.
3) x-intercept => y = 0
=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1
=> - x + 2 = 0 => x = 2
The x-intercept is x = 0
4) y-intercept => x = 0
=> y = - 2 ^ ( -x + 2) + 1= - 2 ^ ( 0 + 2) 1 = - (2)^(2) + 1 =- 4 + 1 = - 3
=> The y-intercept is - 3
5) limit when x -> negative infinite
Lim f(x) when x -> ∞ = - ∞
6) limit when x -> infinite
Lim f(x) when x - > infinite = 1
=> asymptote = y = 1
7) range is the set of values of the fucntion: y
Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1
Range (-∞,1)
Answer:
<em>estimated sales on Wednesday is 19000 pounds.</em>
<em></em>
Step-by-step explanation:
On Monday, he sold 25196 pounds. Estimated to the nearest thousand that is 25000 pounds.
On Tuesday, he sold 18023 pounds. Estimated to the nearest thousand, that is 18000 pounds
Wednesday's sales is unknown. We designate as x
All in all he sold 62409. Estimated to the nearest thousand, that is 62000
The sales on Monday, plus sales on Tuesday, plus sales on Wednesday, must all sum up to the total sales.
25000 + 18000 + x = 62000
43000 + x = 62000
x = 62000 - 43000 = 19000
therefore <em>estimated sales on Wednesday is 19000 pounds.</em>
Answer:
Step-by-step explanation:
Question 1
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = 3; y₁ = -5; m = -4
Substitute the values
The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).
Question 2
x₁ = -1; y₁ = 8; m = 1
Substitute the values
The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).
Answer:
y=-6
Step-by-step explanation:
1. plug in the values, it will be y=4/3(-6) + 2
2. simplify
y=-24/3 + 2
y=-8+2
y=-6
I hope this helped, and if it did, please mark this as brainliest! thanks
