The steel would expand by 4. 8 * 10^-3 cm
<h3>How to determine the linear expansion</h3>
The change in length ΔL is proportional to length L. It is dependent on the temperature, substance, and length.
Using the formula:
ΔL= α LΔT
where ΔL is the change in length L = 10cm
ΔT is the change in temperature = 60° - 20° = 40° C
α is the coefficient of linear expansion = 1.2 x 10^-5 °C
Substitute into the formula
ΔL = 
ΔL = 
cm
Therefore, the steel would expand by 4. 8 * 10^-3 cm
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83.33km per second.
Speed = distance ÷ time.
Speed = 300 ÷ 3.60000
Speed = 83.33km per second
hope that helps.
Answer:
4
Explanation:
You assume that when they were writing two zeroes after the decimal point, they wanted to show that these are significant in determining the precision of this number.
Answer:
a= 8.74 m/s²
Explanation:
Given that
m = 21 kg
θ = 13◦
F= 210 N
g= 9.8 m/s²
The force due to gravity
F₁= m g sinθ
F₁=12 x 9.8 x sin 13◦
F₁=26.45 N
Lets take acceleration is a m/s²
Form Newtons second law
F - F₁ = m a
210 - 26.45 = 21 x a
a= 8.74 m/s²
Well, Break the problem up into parts.
For speeding up:
The car accelerates at 4 m/s^2 for 3 seconds. Multiplying these values tells you the car reaches a speed of 12 m/s.
Vf^2 = Vi^2 + 2a(Xf - Xi)
12^2 = 0 + 2(4)(Xf - 0)
144 = 8 Xf
Xf = 18 m
For coasting:
The car is at the 12 m/s and does this for 2 seconds.
x = vt = (12)(2) = 24 m
For slowing down:
The car decelerates at 3 m/s^2 to come to a stop at the next sign. From 12 m/s, this would take 12/3 seconds or 4 s.
Vf^2 = Vi^2 + 2a(Xf - Xi)
0 = 12^2 + (2)(-3)(Xf - 0)
-144 = -6 Xf
Xf = 24 m
Summing the distances: Xtotal = 18 + 24 + 24 = 66 m
