I am certain your answer is true.good luck
Answer:
Two
Explanation:
Consider the sequence ATGACATGCAATTGA.
Originally, there are 5 codons, translating to a minimum of 5 amino acids: ATG CAT GTC AAT TGA.
A base was inserted after the first G and the third T was deleted, the sequence become (assuming A is the inserted base);
ATG <em>ACA TGC</em> AAT TGA
<em>Only the second and the the third codon are changed and hence, their respective amino acid.</em>
Answer:
(a) number of strands (n) = time (t) ÷ proportionality constant (k)
(b) The time needed for the bacterial to double its initial size is 3.36 hours.
Explanation:
(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n
t is proportional to n, therefore, t = kn (k is the proportionality constant)
Since t = kn, then, n = t/k
(b) Initial amount of strands = 300
Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360
k = t/n = 2/360 = 0.0056 hour/strand
Double of the initial size is 600 (300×2 = 600)
Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours
