9(3x+6)-6(7x-3)=12 solve and check

Find f(b-2) if f(x) = x^2-6x+1

jasenka [17]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent expression is ~

$f(b - 2) = {b}^{2} - 10b + 17$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's evaluate f(b - 2) ~

$f(x) = {x}^{2} - 6x + 1$

$f(b - 2) = (b - 2) {}^{2} -6 (b - 2) + 1$

$\mathcal{ {f(b - 2) = {b}^{2} + 2 {}^{2} - (2 \times b \times 2) - 6b + 12}}$

$f(b - 2) = {b}^{2} + 4 - 4b - 6b + 12 + 1$

$f(b - 2) = {b}^{2} - 10b + 17$

4 0

2 years ago

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Simple math! i'll mark you if you get it right

Ostrovityanka [42]

Answer:

C

Step-by-step explanation:

2 in this case is the weight and 34 is pounds

the graph is 100% proportional

4 0

2 years ago

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Solve for y , what is 9x+3y=4 ??

lora16 [44]

To solve for y, isolate the variable to one side.
9x+3y=4
-9x -9x
~~~~~~~~
3y= -9x+4
~~~~~~~~
3y= -9x+4 (Divide both sides by 3)

y=-3x+4

4 0

2 years ago

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

zhenek [66]

ANSWER

The vertical asymptotes are

$\Rightarrow x=2\:or\:x=-1$

<u>EXPLANATION</u>

We have

$f(x)=\frac{x^2+4}{4x^2-4x-8}$

For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

$4x^2-4x-8=0$

$\Rightarrow x^2-x-2=0$

We split the middle term to obtain,

$x^2+x-2x-2=0$

$\Rightarrow x(x+1)-2(x+1)=0$

$\Rightarrow (x-2)(x+1)=0$

$\Rightarrow x=2\:or\:x=-1$

Therefore the vertical asymptotes are

$x=2\:or\:x=-1$

3 0

3 years ago

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PLEASE HELP :'))

andreev551 [17]

Answer:

D) 54 cm

Step-by-step explanation:

We can use the Centroid Theorem to solve this problem, which states that the centroid of a triangle is $\frac{2}{3}$ of the distance from each of the triangle's vertices to the midpoint of the opposite side.

Therefore, $R$ is $\frac{2}{3}$ of the distance from $U$ to $V$ , since the latter is the midpoint of the side opposite to $U$ . We know this because $R$ belongs to $UV$ , so $R$ must be $QS$ 's midpoint due to the fact that by definition, the centroid of a triangle is the intersection of a triangle's three medians (segments which connect a vertex of a triangle to the midpoint of the side opposite to it).