Answer:
61,940
Step-by-step explanation:
For a recursive sequence of reasonable length, it is convenient to use a suitable calculator for figuring the terms of it. Since each term not only depends on previous terms, but also depends on the term number, it works well to use a spreadsheet for doing the calculations. The formula is easily entered and replicated for as many terms as may be required.
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The result of executing the given algorithm is shown in the attachment. (We have assumed that g_1 means g[-1], and that g_2 means g[-2]. These are the starting values required to compute g[0] when k=0.
That calculation looks like ...
g[0] = (0 -1)×g[-1] +g[-2} = (-1)(9) +5 = -4
The attachment shows the last term (for k=8) is 61,940.
Answer:
the value of hi changes from 58 to 0:
h(t) = -4.9t^2 +19.8t
Step-by-step explanation:
If the initial height changes, then the term in the equation that represents that height will change. The initial height term is hi, so it changes from 58 to 0.
Answer:
short story has 32 pgs
novel has 416 pgs
Step-by-step explanation:
a novel (N) has 13 times as many pages as a short story (x) so, N = 13X
total pages is the equation N + x = 448
plug the equation for N into this
13x + x = 448, combine like terms
14x = 448, divide both sides by 14
x = 32. so now we know that the short story has 32 pages. subtract that from 448. and the novel has 416 pages.
Answer:
Step-by-step explanation:
Asymptotes 3
g(x) =
Factors of denominator will be,
x² - 3x - 10 = x² - 5x + 2x - 10
= x(x - 5) + 2(x - 5)
= (x + 2)(x - 5)
Therefore, factored form of g(x) will be,
g(x) =
Asymptotes 4
h(x) =
=
=
=
Answer:
Quadrant 2
Step-by-step explanation:
The answer is quadrant two because the answer is in the form of -x,y. When the x is negative and the y is positive, it is always going to be in quadrant 2. As you can see in the image below, quadrant 1 is going to be all positive, quadrant two is going to be negative then positive, quadrant three is going to be all negative, and quadrant 4 is going to be positive then negative. Use this as a guide for the rest of your question. I hope this helps!