Y^3x + y^2x^2 = 6
<span>Using implicit differentiation </span>
<span>
3 y^2.y'.x+y^3+2 y.y'.x^2+2 y^2.x=0
</span>
<span>y'(3 y^2.x+2 y. x^2) = -y^3-2 y^2.x </span>
<span>
y' = -[y^2(y+2 x)]/[x y(3 y+2 x)] </span>
<span>
= -[y(y+2 x)]/[x(3 y+2 x)] </span>
<span>
Substituting x =2 and y = 1:
</span>
<span>y' = -(1)(1+4)/[2(3+4)] </span>
<span> = -5/14 </span>
<span>The slope of the tangent of the curve at (2,1) will be:
m = -5/14</span>
The answer is 4,000. hope this helps.
Answer:
its c and d i believe if its wrong im so sorry
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
(f-g)(x) means that the 2 functions are being subtracted.
+10x -(5x-3) = +10x-5x+3
simplify!
+5x+3
the answer is A
The red arc is named "minor arc EF" or simply "arc EF". This is the shortest distance from E to F along the curve.
The measure of arc EF is 68 degrees as this is the central angle that subtends this same arc.