Use trigonometric identities, algebraic methods, and inverse trigonometric functions, as necessary, to solve the following trigo
nometric equation on the interval [0, 27).Round your answer to four decimal places, if necessary. If there is no solution, indicate "No Solution."Scos(x) - 5 = 0
1 answer:
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AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
Therefore AB is 9 cms.
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
Therefore AB is 9 cms.