We are given to lines XY and VW. Now we need to determine the expression that correctly states that these lines are congruent. One possibility to prove that they're congruent is if they are two separate lines and:
XA is congruent to VB,
AY is congruent to BW
XA + AY = XY
VB + BW = VW
Then we can conclude that if the statements above are true, XY and VW must be congruent to each other.
Another possibility is that they are two sides of an isosceles rectangle XYVW and are opposite sides of the rectangle. <span />
Step-by-step explanation:
First
Outer
Inner
Last
First- 5x*2x=10x^2
Outer-5x*-1= -5x
Inner--7*2x= -14x
Last- -7*-1= 7
10x^2-5x-14x+7
you can simplify it further however thats the answer
Answer:
The type of sampling used is the Cluster sampling technique.
Step-by-step explanation:
- Random Sampling
In random sampling, each passenger would have an equal chance of being surveyed. If this particular scenario wanted to use random sampling, they would have used computer generated random passenger numbers and surveyed them, not just passengers all on the same bus picked randomly.
- Systematic sampling is easier than random sampling. In systematic sampling, a particular number, n, is counted repeatedly and each of the nth passengers is picked to be sampled.
- Convenience Sampling
This is the worst sampling technique. It is also the easiest. In Convenience sampling, the surveyor just surveys the first set of passengers that they find.
- Stratified Sampling
Stratified sampling divides the population into groups called strata. A sample is taken from each of these strata using either random, systematic, or convenience sampling.
- Cluster sampling
Cluster Sampling divides the population into groups which are called clusters or blocks (the different buses). The clusters are selected randomly, and every element in the selected clusters is surveyed (each passenger on the selected buses, is surveyed!). Evidently the answer to the question!
Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if and then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p