Answer:
Explanation:
Total momentum of the system before the collision
.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left
If v be the velocity of the stuck pucks
momentum after the collision = 2 v
Applying conservation of momentum
2 v = - .75
v = - .375 m /s
Let after the collision v be the velocity of .5 kg puck
total momentum after the collision
.5 v + 1.5 x .231 = .5v +.3465
Applying conservation of momentum law
.5 v +.3465 = - .75
v = - 2.193 m/s
2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.
Kinetic energy before the collision
= 2.25 + 1.6875
=3.9375 J
kinetic energy after the collision
= .04 + 1.2 =1.24 J
So kinetic energy is not conserved . Hence collision is not elastic.
3 ) Change in the momentum of .5 kg
1.5 - (-1.0965 )
= 2.5965
Average force applied = change in momentum / time
= 2.5965 / 25 x 10⁻³
= 103.86 N
Answer:
31ohms
Explanation:
in a series u add all the ohms together
Answer:
Explanation:
Given:
- thickness of the base of the kettle,
- radius of the base of the kettle,
- temperature of the top surface of the kettle base,
- rate of heat transfer through the kettle to boil water,
- We have the latent heat vaporization of water,
- and thermal conductivity of aluminium,
<u>So, the heat rate:</u>
<u>From the Fourier's law of conduction we have:</u>
where:
area of the surface through which conduction occurs
temperature of the bottom surface
is the temperature of the bottom of the base surface of the kettle.
When sphere A and B are brought in contact and separated, charge on each sphere becomes [2x10^-6 + (-4x10^-6)]/ 2 = -1x10^-6 C.
That is, charge is equally separated and is the average of charges on both spheres. The reason behind equal charge on both spheres after separation is, when they are kept in contact, their potential difference becomes same.
Air resistance doesn't appear in the formula for gravitational force, because it doesn't affect it. Mass does because it does.