Answer:
A and D
Step-by-step explanation:
pls make me brainliest
Answer:
Step-by-step explanation:
f"(x)=2
integrating
f'(x)=2x+c
f'(1)=2+c=4
c=4-2=2
f'(x)=2x+2
integrating
f(x)=2x^2/2+2x+a
f(x)=x^2+2x+a
f(2)=-2
(2)^2+2(2)+a=-2
4+4+a=-2
a=-2-8=-10
f(x)=x^2+2x-10
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
-4
Step-by-step explanation:
-4z² + z²
let's assume you have z² and you're owing 4z², you'll pay the z² you have and you'll still owe 4
so that is -4
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