Y² + 8y + 15
since 8 and fifteen are positive, that means your factors are going to be positive
(y + )(y + )
What are the factors of 15 that add up to 8?
14 and 15
14^2 = 196
15^2 = 225
225+196 = 421
First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
Step-by-step explanation:
y=mx+b since 6 is the y intercept go up six and back -4 times each since it is the x intercept
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