Question

1 (a) A large stone, initially at rest, falls from the top of a building. The stone takes 3.2s to fall to the ground. For this stone, air resistance can be ignored.
(i) Stating the formula that you use, show that the speed of the stone when it hits the ground is 32 m/s.​

Answer 1

The formula that can be used to show that the speed of the stone when it hits the ground is 32 m/s is v = u + at

According to equations of motion,

v = u + at

v = Final velocity

u = Initial velocity

t = Time

a = Acceleration due to gravity

t = 3.2 s

a = 10 m / s²

v = 0 + ( 10 * 3.2 )

v = 32 m /s

Equations of motion are used to describe the position of a moving object in a constantly accelerated manner. The position can be described using acceleration, velocity, displacement and time.

Therefore, the formula that can be used to show that the speed of the stone when it hits the ground is 32 m/s is v = u + at

To know more about equations of motion

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