When a certain lottery has 33 numbers. the different ways can 6 of the numbers be selected is 1107568 ways.
<h3>How to calculate the value?</h3>
From the information, the certain lottery has 33 numbers and we want to know how many different ways can 6 of the numbers be selected.
It should be noted that in this case, we will use combination. This will be illustrated thus:
n = 33
p = 6
Therefore, the combination will be:
C(33, 6)
= 33! / (33 - 6)! × 6!
= 1107568 ways
Learn more about combinations on:
brainly.com/question/4658834
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A certain lottery has 33 numbers. In how many different ways can 6 of the numbers be selected?
