Their boiling points tend to increase with chain length.<span>
</span>
Answer:
The glycosylation reaction or glycoside formation is an organic reaction in which the hemiacetal group of cyclists ketoses or aldoses turns into acetals, named glycosides. Reaction in the attached picture.
Explanation:
Carbohydrates can be found in an open-chain form or a cyclic form. For the second one, the carbonyl group of the aldehyde could react with the alcohol group of the molecule to form the cycle. As shown in the attached picture, the alcohol group of this cyclic form could react with an alcohol (like methanol) in acidic conditions to form an acetal. These compounds are stable at neutral and acidic conditions, but they hydrolyze at basic conditions. This reaction produces both acetals anomers (α and β) because the attack of the nucleophile (alcohol) could be from both sides. However, the most stable anomer will predominate.
Answer: 2.17 x 10^23 molecules
Explanation:
1mole of H2O contains 6.02x10^23 molecules.
Therefore 0.360mole of H2O will contain = 0.36 x 6.02x10^23 = 2.17 x 10^23 molecules
A) GPS monitoring and satellite imagery of crustal movements
Explanation:
The most recent evidence supporting the theory of plate tectonics is the use of GPS monitoring and satellite imagery of crustal movements.
GPS denotes Global Positioning Systems.
Satellite imagery is a recent advancement in the study of moving plates.
- The global positioning system uses the position of a system of satellites in space to delineate positions on earth.
- It works on the principles of triangulation and this helps to fix positions of objects on the earth surface.
- With this, the change in position of the plates can be recorded by known fixed positions of objects.
- Satellite imagery helps to map changes in terrain with time.
- Images can be correlated through time and the shift in terrains delineated.
learn more:
Wegener brainly.com/question/5002949
#learnwithBrainly
Answer:
#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.
Explanation:
Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆
1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.
=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP
2. Calculate moles of F₂ used
=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used
3. Calculate moles of XeF₆ produced from reaction ratios …
Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆
4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number (6.02 x 10²³ molecules/mole)
=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)
= 2.75 x 10²³ molecules XeF₆.