The graph that gives the best representation of the scenario is: option 1 (A).
<h3>Graph of Distance vs Time</h3>
- A typical graph of distance vs time shows the distance covered as against time.
- If the graph shows a line that slopes upwards, it implies movement from a spot, if it shows an horizontal line, it implies a rest.
The first graph is the correct one that best represents the scenario because it starts at the point of origin (0, 0), which means the bird covers not distance at zero time when it is still at its nest.
As the bird flies, distance increases with time till it stopped at a point to eat.. This is represented by horizontal line, meaning time increased but distance from the nest remains the same.
The upward slope from the spot represents the further distance the bird is flying in search for more food.
Therefore, the graph that gives the best representation of the scenario is: option 1 (A).
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the upside down T is always perpendicular so the answer is b. :)
Answer:
Step-by-step explanation:
a1 = 7
a2 = 4(7) = 28
a3 = 4(28) = 112
a4 = 4(112) = 448
a5 = 4(448) = 1792
a6 = 4(1792) = 7168
Answer:
= 9
Step-by-step explanation:
The given parameters are;
The point of intersection of the perpendicular bisectors of the sides , , and intersect (meet) at point G
Let D represent the point of intersection of the perpendicular bisector from G to , we have for ΔBGD and ΔCGD;
≅ by reflexive property
∠GDB = ∠GDC = 90° given that is the perpendicular bisector of
Similarly, ≅ , also given that is the perpendicular bisector of
Therefore;
ΔBGD ≅ ΔCGD by Side-Angle-Side (SAS) rule of congruency
≅ by Congruent Parts of Congruent Triangles are Congruent, (CPCTC)
= = 9 by definition of congruency
∴ = 9.
ANSWER
EXPLANATION
We want to solve
where
We reciprocate both sides of this trigonometric equation to obtain:
We take arctangent of both sides to get;
This is the principal solution.
The tangent ratio is also positive in the third quadrant.
The solution in the third quadrant is